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67 lines
2.0 KiB
Python
67 lines
2.0 KiB
Python
# Copyright (c) Microsoft Corporation.
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# Licensed under the MIT License.
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import tilelang
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import tilelang.testing
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from tilelang import tvm as tvm
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import tilelang.language as T
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def matmul(M, N, K, block_M, block_N, block_K, dtype="float16", accum_dtype="float"):
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num_stages = 0
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@T.prim_func
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def matmul(
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A: T.Buffer((M, K), dtype),
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B: T.Buffer((K, N), dtype),
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C: T.Buffer((M, N), dtype),
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):
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with T.Kernel(T.ceildiv(N, block_N), T.ceildiv(M, block_M), is_cpu=True) as (bx, by):
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A_local = T.alloc_local((block_M, block_K), dtype)
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B_local = T.alloc_local((block_K, block_N), dtype)
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C_local = T.alloc_local((block_M, block_N), accum_dtype)
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T.clear(C_local)
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# Apply layout optimizations or define your own layout
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# (Optional).
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# T.annotate_layout(
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# {
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# A_local: make_swizzle_layout(A_local),
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# B_local: make_swizzle_layout(B_local),
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# }
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# )
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for ko in T.Pipelined(K // block_K, num_stages=num_stages):
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T.copy(A[by * block_M, ko * block_K], A_local)
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# Or Copy with Parallel
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for k, j in T.Parallel(block_K, block_N):
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B_local[k, j] = B[ko * block_K + k, by * block_N + j]
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for i, j, k in T.grid(block_M, block_N, block_K):
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C_local[i, j] += A_local[i, k] * B_local[k, j]
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T.copy(C_local, C[by * block_M, bx * block_N])
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return matmul
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def assert_matmul_codegen(M=1024, N=1024, K=1024, block_M=128, block_N=128, block_K=32):
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func = matmul(M, N, K, block_M, block_N, block_K)
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rt_mod, _ = tilelang.lower(func, target="c")
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code = rt_mod.imported_modules[0].get_source()
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assert code is not None, "Code generation failed"
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def test_matmul_codegen():
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assert_matmul_codegen(M=1024, N=1024, K=1024, block_M=128, block_N=128, block_K=32)
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if __name__ == "__main__":
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tilelang.testing.main()
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