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scriptc/tests
Chris Tate 478feb15cd Call the declared base method for super calls in JavaScript method values
Since 76735a8d9 (#1975), a `super.m()` call in a JavaScript class method
whose `this` is the call-site receiver reflected the base class's whole
prototype and read `m` from it. An instance's member lookup first tests
its property bag, which inherits from its class's prototype data, so once
the base's prototype was reflected, `child[k]` for a method the subclass
overrides found the base's method there: `value[name](arg)` on a subclass
instance called the base method.

While no code reads a prototype method by name, `super.m()` now calls the
declaring class's receiver-independent method value with the receiver, as
the method's [[HomeObject]] lookup answers, without reflecting the base
prototype. Programs that read prototype methods by name keep the
reflected lookup.
2026-10-25 00:26:55 -05:00
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