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Colby MchenryandClaude Opus 5.5
81fd007850
A C++ call written through a namespace, `x::m()`, reached matchMethodCall's name strategies when no declaration of `x::m` was found by qualified name. They can only return a method of some class, which a namespace never holds: the capitalized-receiver class (`internal` → a class `Internal`), the one method of the name in the project, or the best receiver-word guess. So protocolbuffers/protobuf's `absl::StripPrefix(name, …)` linked to its Rust generator's `MultiCasePrefixStripper::StripPrefix` and `absl::Status(…)` to `upb::Status`'s constructor. fmtlib/fmt's `fmt::ptr(p)` linked to a test scanner's `ptr()` method, and `fmt::day(…)` to a test's `date::day`, ahead of the step that reads the namespaces a macro opens and finds fmt's own `ptr` function and `day` alias in `FMT_BEGIN_NAMESPACE`. Those strategies now return nothing when the qualifier is a namespace (isCppNamespaceQualifier): a lowercase name that no C or C++ type or alias node has, and that the calling file declares as neither a template parameter nor an alias (cppNamesBroughtIn, now split into type names and namespace names, since a namespace the file opens confirms it is one). rocksdb's `hash_table::Insert(…)` through `typedef HashTable<…> hash_table;` keeps its edge. So does the constructor of a class the call names in that namespace (isCppConstructorThrough): protobuf's `internal::SourceWrapper<absl::Cord>(&data)` constructs `struct SourceWrapper<absl::Cord>`, a specialization the index holds without its name, whose template is only declared. A method of another template's specialization is no constructor: fmt's `fmt::scan<int>(…)` is fmt's `scan` function, not `scanner<num>::scan`. The check runs only where one of those strategies would return. Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>